Question

Ok the output is supposed to look like this:

./a 3 4 8 2   3   4   8   2   

This is what I have so far, but I am lost and can only get the first integer to print (we have to use GetInt, which gets the specified integer in the string):

int main (int argc, char*argv []){      int v;        int i;      i = 1;      v = GetInt(argc, argv, i + 1);       if(argc >= 1){         printf('%d\n', GetInt(argc, argv, i));      }      return 0;   }   

Answer 1

Without actually seeing your implementation of GetInt, something like this (Assumes C90):

#include <stdio.h>  int GetInt( int argc, char* argv[], int i ) {     /*       * you may want to use sscanf, strtol or other functions,      * but you haven't specified      */     return atoi( argv[i] ); }  int main ( int argc, char* argv[] ) {     int i;     for ( i = 1; i < argc; ++i ) {         printf( '%d\n', GetInt( argc, argv, i ) );     }     return 0; } 

Returns:

$ ./a.out 3 4 8 2 3 4 8 2 

Error checking omitted and such. It is an exercise to you to figure out how to deal with non-decimal arguments.