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Home/ Questions/Q 6847993
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Editorial Team
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Editorial Team
Asked: May 27, 20262026-05-27T00:48:45+00:00 2026-05-27T00:48:45+00:00

Okay, essentially this is what the script looks like: echo -n Guess my number:

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Okay, essentially this is what the script looks like:

echo -n "Guess my number: "
read guess

while [ $guess != 5 ]; do
echo Your answer is $guess. This is incorrect. Please try again.
echo -n "What is your guess? "
read guess
done

echo "That's correct! The answer was $guess!"

What I want to change is this line:

while [ $guess != 5 ]; do

To something like this:

while [ $guess != 5 and $guess != 10 ]; do

In Java I know “and” is ” && ” but that doesn’t seem to work here. Am I going about this the right way using a while loop?

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  1. Editorial Team
    Editorial Team
    2026-05-27T00:48:46+00:00Added an answer on May 27, 2026 at 12:48 am

    The [] operator in bash is syntactic sugar for a call to test, which is documented in man test. “or” is expressed by an infix -o, but you need an “and”:

    while [ $guess != 5 -a $guess != 10 ]; do
    
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