Question

Okay I know right off the bat this is going to be a stupid question, but I am not seeing why this simple C program is not compiling.

#include <stdio.h>
#include <stdlib.h>
typdef struct CELL *LIST;
struct CELL {
    int element;
    LIST next;
};
main() {
    struct CELL *value;
    printf("Hello, World!");
}

I am new to C programming, not to programming in general, but to C. I am familiar with Objective-C, Java, Matlab, and a few others, but for some reason I can not figure this one out. I am trying to compile it using GCC in OS X if that makes a difference. Thanks for your help!

The error message I am getting is

functionTest.c:5: error: expected specifier-qualifier-list before ‘LIST’
functionTest.c:7: error: expected ‘=’, ‘,’, ‘;’, ‘asm’ or ‘__attribute__’ before ‘struct’

Answer 1

Most importantly: You have misspelled typedef.

Then, at least these days, we normally add a return type to main, like so:

int main()

Also, main is supposed to return the exit status, so:

#include <stdio.h>
#include <stdlib.h>

typedef struct CELL *LIST;

struct CELL {
  int element;
  LIST next;
};

int main() {
  struct CELL *value;
  printf("Hello, World!\n");
  return 0;
}