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Home/ Questions/Q 1106677
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Editorial Team
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Editorial Team
Asked: May 17, 20262026-05-17T01:49:44+00:00 2026-05-17T01:49:44+00:00

Okay, I really know this has GOT to be the long way around doing

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Okay, I really know this has GOT to be the long way around doing this… however, what I want is relatively simple one would think. I have a database with a timestamp column. I am using iPhone SDK with SQLite3. I want to have SQLite3 get all records for today (where timestamp >= midnight this morning) ..

What i have come up with (that works) is the following. BUT there has to be a way better way. This one takes far too many steps to be the best way to do it. (I want SQLite3 to figure the timestamp itself … so please do not tell me to use the NSDate with NSCalendar, etc.)

select * from table where timestamp >= strftime('%s','now') - (strftime('%S',datetime('now','localtime')) + (strftime('%M',datetime('now','localtime')) * 60) + (strftime('%H',datetime('now','localtime')) * 3600));

There has to be an easier way (one, preferably, where i am not calling datetime and strftime 4 times or more each)

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  1. Editorial Team
    Editorial Team
    2026-05-17T01:49:44+00:00Added an answer on May 17, 2026 at 1:49 am

    You just want records for today, or records for every day after today?

    For today, just do:

    select * from table where strftime('%Y-%m-%d', timestamp) = strftime('%Y-%m-%d', 'now')

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