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Asked: 2026-06-17T09:16:07+00:00

Okay, I’m fairly new to java but I’m learning quickly(hopefully). So anyway here is

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Okay, I’m fairly new to java but I’m learning quickly(hopefully). So anyway here is my problem:

I have a string(For example we will use 2.9), I need to change this to either int or long or something similar that I can use to compare to another number.

As far as I know int doesn’t support decimals, I’m not sure if long does either? If not I need to know what does support decimals.

This is the error: java.lang.NumberFormatException: For input string: "2.9" with both Interger.parseInt and Long.parseLong

So any help would be appreciated!

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1 Answer

  1. Editorial Team

    Both int and long are integer values (being long the representation of a long integer that is an integer with a higher capacity). The parsing fails because those types do not support a decimal part.

    If you were to use them and enforce a casting you’re relinquishing the decimal part of the number.

    double iAmADouble = 100 / 3;
int iWasADouble = (int)iAmADouble; //This number turns out to be 33

    Use double or float instead.

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