Question

Okay, so here is my code:

public static void playAgain(Scanner in){
    System.out.print("Play again?: ");
    String again=in.next();
    if (again.equalsIgnoreCase("y")){
        playerScore=0;
        aiScore=0;
        playAgain=true;
        }
    else if (again.equalsIgnoreCase("n")){
        playAgain=false;
        }
    else {
        while (!again.equalsIgnoreCase("y") && !again.equalsIgnoreCase("n")){
            System.out.print("Invalid response.  Please enter \"y\" or \"n\": ");
            again=in.next();
            }
        }
    }

For some reason, if I input the wrong variable, say ‘boog’, the while loop prints an error message but for some reason defaults to ‘y’ even if I input ‘n’ – for example, a sample run would be:

Play again? boog

Invalid input, please input y or n. n

-program plays again despite my inputting n-

How do I fix this? Is it something with the order? Thanks in advance!

Answer 1

It could be because you are not setting playAgain to false after exiting the while loop. Is the previous value of playAgain true?

I think you need to think about refactoring so that the while loop is above the ‘y’ and ‘n’ if/else statement. That way the if/else is always called once the user has entered a valid value. Validation should be at the start of the method.