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Editorial Team
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Asked: 2026-05-22T03:20:09+00:00

Okay so heres what I have but whenever I do this, I am returned

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Okay so heres what I have but whenever I do this, I am returned with the first record of the database:

<?php
    function getInfo($id,$slot){
        if(!$id){ return '<b>Error</b> Id Not Returned. Please contact support@site.com for more information.'; }
        $mm = mysql_query("SELECT * FROM `users` WHERE `id`='".$id."'");
        $mma = mysql_fetch_assoc($mm);
        $p = $mma[$slot];
        return $p;
        //return $id; <- Debug (Returns ID given)
    }
$post = preg_replace("/\[CallName]([^]]+)\[\/CallName\]/", getInfo('\\1',"fullname"), $post);
?>
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1 Answer

  1. Editorial Team

    I’m surprised you’re getting anything returned…your preg_replace pattern should be giving you an error (you aren’t escaping some of your brackets). But anyways, you can’t pass a captured group to your function like that. You have to use the “e” pattern modifier (look at example #4 in the preg_replace manual

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