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Home/ Questions/Q 891411
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Editorial Team
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Editorial Team
Asked: May 15, 20262026-05-15T13:53:13+00:00 2026-05-15T13:53:13+00:00

Okay, so I’m getting my MySQL Version like so: preg_replace(‘#[^0-9\.]#’, ”, mysql_get_server_info()); Which gives

  • 0

Okay, so I’m getting my MySQL Version like so:

preg_replace('#[^0-9\.]#', '', mysql_get_server_info());

Which gives me a number like: 5.1.36

That’s all good. What I need to do, is compare that version with another version. I was about to attempt to write my function to compare them, when I thought of version_compare(). However, upon testing I became unsure, but perhaps I’m just not sure how MySQL Version Numbers work.

This is what I tested:

version_compare('5.1.36', '5.1.4', '<');

or

5.1.36 < 5.1.4

I assumed that this would return true, that 5.1.36 is less than 5.1.4. My reason for that is, I figure 5.1.4 is actually 5.1.40 not 5.1.04. Perhaps I’m wrong there.

So am I thinking wrong, or is the function returning the incorrect result?

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  1. Editorial Team
    Editorial Team
    2026-05-15T13:53:13+00:00Added an answer on May 15, 2026 at 1:53 pm

    The function is correct. The numbering system is M.m.r where each “number” is a decimal number.

    • M is the major version number
    • m is the minor version number
    • r is the revision number

    So 5.1.36 would be revision 36 of the 5.1 minor version… Therefore, 5.1.4 would be revision 4 (and hence 36 > 4)…

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