Okay so part two on this. I restructured the code on this but now I can’t figure out a way to return back the empWeeklyPay without initializing it to zero. And if I initialize it to zero then my pay will always be zero? Can anyone think of anything I can do?
public double getWeeklyPay()//Call the getWeeklyHours method of the Emp's timecard to get the total
//hours worked and then multiply the returned value by the emp's hourly rate and return the value.
{
TimeCard empTimeCard = timeCard;
double empWeeklyPay;
double totalOtHours;
double totalRegHours;
int i = 0;
while(i <= empTimeCard.NUMDAYS && empTimeCard.getHoursByDay(i) > 8)
{
double empHourlyRate = getHourlyRate();
double otHours = 0;
double regHours = 0;
double sumOtHours = 0;
int sumRegHours = 0;
//grabbing the overtime and reghours and storing them
otHours = empTimeCard.getHoursByDay(i) % 8;
regHours = empTimeCard.getHoursByDay(i) - otHours;
sumOtHours += otHours;
sumRegHours += regHours;
double tmpBasePay = (sumRegHours * empHourlyRate) + (sumOtHours * empHourlyRate * 1.5);
if(Integer.toString(getEmployeeId()).charAt(0) == '0' || Integer.toString(getEmployeeId()).charAt(0) == '2'
|| Integer.toString(getEmployeeId()).charAt(0) == '9')
//Java reads in 1010 so need to convert to a string to do a count on the value.
{
tmpBasePay += (tmpBasePay * .10);
i++;
}
else if(Integer.toString(getEmployeeId()).charAt(0) == '3')
{
tmpBasePay -= (tmpBasePay *.10);
i++;
}
else if(Integer.toString(getEmployeeId()).charAt(0) == '8')
{
tmpBasePay += (tmpBasePay * .20);
i++;
}
totalRegHours = regHours;
totalOtHours = sumOtHours;
if(totalRegHours > 34)
{
tmpBasePay -= (tmpBasePay * .06);
//empWeeklyPay = tmpBasePay;
empWeeklyPay = tmpBasePay;
}
else
{
empWeeklyPay = tmpBasePay;
}
}
return empWeeklyPay;// <---need to return back this value.
Here is the answer to my question. I was able to figure it out. Please see code below in case someone else faces this same problem in the near or distant future: