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Home/ Questions/Q 8733429
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Editorial Team
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Editorial Team
Asked: June 13, 20262026-06-13T09:38:59+00:00 2026-06-13T09:38:59+00:00

Okay so right now I have essentially this code: class a { public void

  • 0

Okay so right now I have essentially this code:

class a {

public void ab() {
    b thread = new b();
     thread.bb(this);
    }
}

class b {

    public void bb(a _a) {
     //execute code here in new thread so ab can continue running
    }
}

However this doesn’t open it in a new thread, and yes I did research this, all the solutions I found didn’t leave any option to send a parameter (this) to the bb method

How to call class.method in new thread that requires a parameter?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-13T09:39:00+00:00Added an answer on June 13, 2026 at 9:39 am

    To start a thread, you must have an instance of java.lang.Thread, of which b is not. You can extend thread to achieve this.

    class b extends Thread {
    

    A Thread runs asynchronously whatever you place in its run() method, which you can override from its original (empty) implementation.

    class b extends Thread {
    
        @Override
        public void run() {
        }
    }
    

    However, this doesn’t allow you to pass an instance of a. Your best option here is to take an instance of a as an instance variable in the constructor of b.

    class b extends Thread {
    
        private final a _a;
    
        public b(a _a) {
            this._a = _a;
        }
    
        @Override
        public void run() {
            //now you can use _a here
        }
    }
    

    Finally, to run the thread asynchronously, you don’t call the newly implemented run() method, but you call Thread#start(), which invokes the run() method in a new thread.

    class a {
    
        public void ab() {
            b thread = new b(this);
            thread.start();
        }
    }
    

    As a side note, standard Java convention is to start class names with capital letters, so you should rename a to A and so forth. This however won’t make any difference as far as compilation or execution goes.

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