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Home/ Questions/Q 506795
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Editorial Team
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Editorial Team
Asked: May 13, 20262026-05-13T06:44:17+00:00 2026-05-13T06:44:17+00:00

Okay so this query should be easy but I’m having a bit of difficult.

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Okay so this query should be easy but I’m having a bit of difficult. Let’s say I have a table called ‘foo’ with columns ‘a’, ‘b’.

I’m trying to figure out the following in one query:

select how of column ‘a’ are available of type column ‘b’, this is done with the following:

mysql> select count(a),b from foo GROUP BY b;

that’s straight forward. but now I want to add a third output to that query as well which shows the percentage of the result from count(a) divided by count(*). So if I have 100 rows total, and one of the GROUP BY results comes back with 20, I can get the third column to output 20%. Meaning that column a makes for 20% of the aggregate pool.

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  1. Editorial Team
    Editorial Team
    2026-05-13T06:44:17+00:00Added an answer on May 13, 2026 at 6:44 am

    Assuming you have > 0 rows in foo

    SELECT count(a), b, (count(a) / (SELECT count(*) FROM foo)) * 100
    FROM foo
    GROUP BY b
    
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