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Editorial Team
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Editorial Team
Asked: May 12, 20262026-05-12T05:29:03+00:00 2026-05-12T05:29:03+00:00

Okay so this was driving me nuts all day. Why does this happen: class

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Okay so this was driving me nuts all day.

Why does this happen:

class Foo:
    def __init__(self, bla = {}):
        self.task_defs = bla
    def __str__(self):
        return ''.join(str(self.task_defs))

a = Foo()
b = Foo()
a.task_defs['BAR'] = 1
print 'B is ==> %s' % str(b)
print 'A is ==> %s' % str(a)

Gives me the output:

B is ==> {'BAR': 1}
A is ==> {'BAR': 1}

I know it has to do with python passing everything by reference.

But why does this happen? This was literally making me go insane all day, basically causing me to tear my stuff apart. Shouldn’t python be smart enough to deal with something like this?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-12T05:29:04+00:00Added an answer on May 12, 2026 at 5:29 am

    Since you have bla initially set to a mutable type (in this case a dict) in the arguments, it gets shared since bla doesn’t get reinitialized to a new dict instance for each instance created for Foo. Here, try this instead:

    class Foo:
        def __init__(self, bla=None):
            if bla is None:
                bla = {}
            self.task_defs = bla
        def __str__(self):
            return ''.join(str(self.task_defs))
    
    a = Foo()
    b = Foo()
    a.task_defs['BAR'] = 1
    print 'B is ==> %s' % str(b)
    print 'A is ==> %s' % str(a)
    
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