Question

On ClearCase I use the following command to find all the elements that have the foo attribute with the value "yes":

cleartool find . -ver 'foo == "yes"' -print

Is there a way to retrieve in a single command the elements that have the foo attribute with the value either "yes" or "maybe"?

Answer 1

The || operator should be supported here:

cleartool find . -ver 'foo == "yes" || foo="maybe"' -print
# or
cleartool find . -ver {'foo == "yes" || foo="maybe"'} -print
# or
cleartool find . -ver \{'foo == "yes" || foo="maybe"'\} -print

See this more elaborate example for instance:

with one attribute and state but not a second attribute and state, and then create the second attribute and state

cleartool find . -version \{CIstate=="Approved"  && !PRCR_controlled=="ClearQuest_Controlled" && version(/main/LATEST)}\ ' -exec \'cleartool mkattr PRCR_controlled \"ClearQuest_Controlled\" \”$CLEARCASE_XPN\”\'

The section “logical operator” details how they are used:

The cleartool find command can be used with the QUERY LANGUAGE to take advantage of logical operators.
Review the IBM Rational ClearCase Information Center on the topic of query_language (cleartool man query_language) for more details.

Example:

Use the cleartool find command with the logical not (!) & and (&&) operators to find all versions for an element that are not labeled with either of two label types in the VOB.

cleartool find . -version !"lbtype(tested) && !lbtype(release) " -print