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Home/ Questions/Q 6040079
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Editorial Team
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Editorial Team
Asked: May 23, 20262026-05-23T06:27:44+00:00 2026-05-23T06:27:44+00:00

on my quest to learn and improve my JavaScript I came across a script

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on my quest to learn and improve my JavaScript I came across a script that has a switch / case statement and I noticed some variables are incremented using ++ with the variable before the ++ and then some variables have the ++ after the variable. What’s the difference between these? Here’s an example of what I’m trying to explain notice the m and y variables.

 switch(f){
        case 0:{

            ++m;
            if(m==12){
                m=0;
                y++;
            }
            break;
        }
        case 1:{

            --m;
            if(m==-1){
                m=11;
                y--;
            }
            break;
        }
        case 2:{

            ++y;
            break;
        }
        case 3:{

            --y;
            break;
        }
        case 4:{

            break;
        }
        }
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  1. Editorial Team
    Editorial Team
    2026-05-23T06:27:45+00:00Added an answer on May 23, 2026 at 6:27 am

    ++i returns the value of i after it has been incremented. i++ returns the value of i before incrementing.

    When the ++ comes before its operand it is called the “pre-increment” operator, and when it comes after it is called the “post-increment” operator.

    This distinction is only important if you do something with the result.

    var i = 0, j = 0;
    
    alert(++i);  // alerts 1
    alert(j++);  // alerts 0
    

    One thing to note though is that even though i++ returns the value before incrementing, it still returns the value after it has been converted to a number.

    So

    var s = "1";
    alert(typeof s++);  // alerts "number"
    alert(s);  // alerts 2, not "11" as if by ("1" + 1)
    
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