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Home/ Questions/Q 8731103
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Editorial Team
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Editorial Team
Asked: June 13, 20262026-06-13T09:09:17+00:00 2026-06-13T09:09:17+00:00

On normal objects, I can do the following: object A { def apply =

  • 0

On normal objects, I can do the following:

object A {
  def apply = "!"
}
A() // "!"

But on package objects, this doesn’t work:

package object A {
  def apply = "?"
}
A.apply // "?"
A() // compile error
    // error: package A is not a value

Is there some fundamental limitation? Or is it just an implementation limitation, which I can fix by tweaking the compiler a bit?

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  1. Editorial Team
    Editorial Team
    2026-06-13T09:09:19+00:00Added an answer on June 13, 2026 at 9:09 am

    The only way you can do it without apply is this:

    A.`package`()
    

    This is because A does not denote a value or a method, and the language specification states that for f() to be valid, f has to have a method type or a value type with an apply method. I have no idea how easily one could “tweak” the compiler to change this, but I doubt it’s worth the effort. If you do want to go to such lengths, it would be easier to just add your method to Predef.

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