Question

On running the following code:

int main()
{
    int a = sizeof(signed) + sizeof(unsigned);
    int b = sizeof(const) + sizeof(volatile);

    printf("%d",a+++b);

    return 0;
}

in visual c++, I get an output as 16. Is the default data type of signed, unsigned, const and volatile considered int?

Answer 1

Its not just these qualifiers, the default type of C language is int. So if you dont specify data type at someplace, the compiler will assume int.

For example if you don’t declare a function and use it, the compiler will give you a warning and assume that the function returns int.