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Home/ Questions/Q 6074255
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Editorial Team
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Editorial Team
Asked: May 23, 20262026-05-23T10:21:43+00:00 2026-05-23T10:21:43+00:00

On the Windows Form application I have a Lamp image (a black and white

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On the Windows Form application I have a Lamp image (a black and white one, and a bright one. For OFF and ON respectively).

Using the Button how can I achieve the scenario such that same button will turn the property of the image (pictureBox in my case) to show the Lamp as ON and pressing the same button again will turn the Lamp off.

I am accessing the ‘Visible’ property of picture box.

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  1. Editorial Team
    Editorial Team
    2026-05-23T10:21:43+00:00Added an answer on May 23, 2026 at 10:21 am

    Put two images on top of each other and get the button to switch which one of them is enabled.

    In the form designer you make one of them visible and the other non-visible. The code in the button handler can then be something like:

    lightImage.Visible = !lightImage.Visible;
    darkImage.Visible = != lightImage.Visible;
    

    That will swap which one is visible and eliminate the need to keep state elsewhere.

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