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Home/ Questions/Q 8963835
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Editorial Team
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Editorial Team
Asked: June 15, 20262026-06-15T16:26:47+00:00 2026-06-15T16:26:47+00:00

Once an exception is caught in this code, the menuSystem method is run, but

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Once an exception is caught in this code, the menuSystem method is run, but once I go to input a number the programme closes and the “Build is successful” message is displayed. Is there any way to get back into the while loop once an exception has occured?

public static void main(String[] args) {
   final UnitResults myUnit = new UnitResults(10, "Java");
   int option = menuSystem();

   try {
      while (option != 0) {
         final Scanner keyb = new Scanner(System.in);
         System.out.println("");
         switch (option) {
         }
      }
   } catch (Exception InputMismachException) {
      System.out.println("\nPlease Enter a Valid Number\n");
      option = menuSystem();
   }
}
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-15T16:26:49+00:00Added an answer on June 15, 2026 at 4:26 pm

    put your try/catch inside your while loop:

        while (option != 0) {
            final Scanner keyb = new Scanner(System.in);
            System.out.println("");
            try {
                switch (option) {
    
                }
            } catch (Exception InputMismachException) {
                System.out.println("\nPlease Enter a Valid Number\n");
                option = menuSystem();
            }
        }
    
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