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Home/ Questions/Q 325883
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Editorial Team
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Editorial Team
Asked: May 12, 20262026-05-12T09:15:29+00:00 2026-05-12T09:15:29+00:00

Once in a while, I find myself rounding some numbers, and I always have

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Once in a while, I find myself rounding some numbers, and I always have to cast the result to an integer:

int rounded = (int) floor(value);

Why do all rounding functions (ceil(), floor()) return a floating number, and not an integer? I find this pretty non-intuitive, and would love to have some explanations!

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  1. Editorial Team
    Editorial Team
    2026-05-12T09:15:29+00:00Added an answer on May 12, 2026 at 9:15 am

    The integral value returned by these functions may be too large to store in an integer type (int, long, etc.). To avoid an overflow, which will produce undefined results, an application should perform a range check on the returned value before assigning it to an integer type.

    from the ceil(3) Linux man page.

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