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Home/ Questions/Q 8736035
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Editorial Team
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Editorial Team
Asked: June 13, 20262026-06-13T10:12:45+00:00 2026-06-13T10:12:45+00:00

One famous programmer said why anybody need DB, just give me hash table!. I

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One famous programmer said “why anybody need DB, just give me hash table!”. I have list of grammar symbols together with their frequencies. One way it’s a map: symbol#->frequency. The other way its a [binary] relation. Problem: get top 5 symbols by frequency.

More general question. I’m aware of [binary] relation algebra slowly making inroad into CS theory. Is there java library supporting relations?

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  1. Editorial Team
    Editorial Team
    2026-06-13T10:12:47+00:00Added an answer on June 13, 2026 at 10:12 am
     List<Entry<String, Integer>> myList = new ArrayList<...>();
     for (Entry<String, Integer> e : myMap.entrySet())
           myList.add(e);
    
     Collections.sort(myList, new Comparator<Entry<String, Integer>>(){
    
        int compare(Entry a, Entry b){
           // compare b to a to get reverse order
           return new Integer(b.getValue()).compareTo(new Integer(a.getValue());
        }
     });
    
     List<Entry<String, Integer>> top5 = myList.sublist(0, 5);
    

    More efficient:

     TreeSet<Entry<String, Integer>> myTree = new TreeSet<...>(
        new  Comparator<Entry<String, Integer>>(){
    
          int compare(Entry a, Entry b){
             // compare b to a to get reverse order
             return new Integer(b.getValue()).compareTo(new Integer(a.getValue());
          }
        });
     for (Entry<String, Integer> e : myMap.entrySet())
           myList.add(e);
    
     List<Entry<String, Integer>> top5 = new ArrayList<>();
     int i=0;
     for (Entry<String, Integer> e : myTree) {
         top5.add(e);
         if (i++ == 4) break;
     }
    
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