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Editorial Team
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Editorial Team
Asked: May 18, 20262026-05-18T19:40:14+00:00 2026-05-18T19:40:14+00:00

One of my colleges seem to have an ‘undefined index’ error on a code

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One of my colleges seem to have an ‘undefined index’ error on a code I wrote

This code of mine looks like this:

if ( is_array ($arr['key'])) 

My intention was to check whether $arr has a key named ‘key’, and if the value of that key is array itself. Should I do instead: if( isset($arr['key']) && is_array ($arr['key'])) ?

Maybe the following is equivavlent:
Let’s assume $var is not set. Then, will is_array($var) cause an error or will it just return false?

Thank you

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  1. Editorial Team
    Editorial Team
    2026-05-18T19:40:16+00:00Added an answer on May 18, 2026 at 7:40 pm

    Yes, use isset, then is_array.

    if(isset($arr['key']) && is_array($arr['key'])) {
        // ...
    }
    

    Because PHP uses short-circuit logic evaluation, it will stop before it gets to is_array(), so you’ll never get an error.

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