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Home/ Questions/Q 3362002
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Editorial Team
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Editorial Team
Asked: May 18, 20262026-05-18T03:13:14+00:00 2026-05-18T03:13:14+00:00

one question I always ask myself is how is it possible that javascript has

  • 0

one question I always ask myself is how is it possible that javascript has still a reference in a callback function of a AJAX request when the variable was declared in the function which isssues the AJAX call. Here an example

var loadMask = {name:"test"};

form.submit({
  url: 'request.php',
  timeout : 180000,
  success: function(the_form, action_object)
  {    
    console.log(loadMask);
  }
});

despite the fact that loadMask was declared outside of the success function it is still visible (and defined) inside.

How is this possible?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-18T03:13:15+00:00Added an answer on May 18, 2026 at 3:13 am

    This is possible using something called closures. There are many resources for this:

    Here’s a few from a google:

    http://www.webreference.com/programming/javascript/rg36/

    http://jibbering.com/faq/notes/closures/

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