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Home/ Questions/Q 8416487
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Editorial Team
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Editorial Team
Asked: June 10, 20262026-06-10T01:46:19+00:00 2026-06-10T01:46:19+00:00

Open a page in Chrome, enter the JavaScript console, and type debugger; . Immediately

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Open a page in Chrome, enter the JavaScript console, and type debugger;. Immediately we hit a breakpoint at line 2 of the following code:

with ((window && window.console && window.console._commandLineAPI) || {}) {
debugger;
}

Can anyone make sense of this? Why the with statement? Why the breakpoint on debugger;?

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  1. Editorial Team
    Editorial Team
    2026-06-10T01:46:21+00:00Added an answer on June 10, 2026 at 1:46 am

    Do you know what debugger is?

    “Invokes any available debugging functionality. If no debugging functionality is available, this statement has no effect.”

    The code is basically saying if there is a console available with this browser and it has the feature “_commandLineAPI”, start up the debugger.

    The “with” statement basically is a catch all way to make sure there is not an error. In reality they should have just used an if.

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