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Editorial Team
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Asked: 2026-06-15T19:42:20+00:00

Oracle 11g How can I write query to get desired results? Specifically, How do

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Oracle 11g
How can I write query to get desired results? Specifically, How do I join to the most recent records in the REQUIREMENTS table?

Selection Criteria:
Most recent detail and most recent requirements

 with 
 detail as (
 select 'TAXI' code, '4920' numb, 1990 dstart, 'BLUE' taxi_name from dual union all
 select 'TAXI' code, '4920' numb, 2000 dstart, 'PINK' taxi_name from dual union all
 select 'TAXI' code, '4920' numb, 2008 dstart, 'CYAN' taxi_name from dual),

 requirement  as (
select 'TAXI' code, '4920' numb,  2 seqno, 2000 rstart,  25,min_age,'CDL',permit from dual union all
select 'TAXI' code, '4920' numb,  4 seqno, 2000 rstart, 27 min_age, 'CAR' permit from dual union all
select 'TAXI' code, '4920' numb,  6 seqno, 2000 rstart, 29 min_age, 'HAZ' permit from dual union all
select 'TAXI' code, '4920' numb,  2 seqno, 2007 rstart, 24 min_age, 'CDL' permit from dual union all
select 'TAXI' code, '4920' numb,  4 seqno, 2007 rstart, 26 min_age, 'VAN' permit from dual union all
select 'TAXI' code, '4920' numb,  6 seqno, 2007 rstart, 28 min_age, 'HAZ' permit from dual

) 

select code,numb,taxi_name, dstart, ranking from (
select code, numb, taxi_name,dstart, rank() over (partition by code, numb 
                                            order by dstart desc ) ranking
from detail)
where ranking =1

Yields

CODE NUMB  NAME  YEAR    
---- ---- -----  ------- 
TAXI 4920 CYAN   2008 


DESIRED OUTPUT
--------------------------
 code numb name        dstart     sqno    rstart   min_age permit
 TAXI 4920 CYAN       2008       2         2007    24      CDL
 TAXI 4920 CYAN       2008       4         2007    26      VAN
 TAXI 4920 CYAN       2008       6         2007    28      HAZ
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1 Answer

  1. Editorial Team

    Well, you essentially have the idea. You just need to apply it to two tables:

    select code,numb,taxi_name, dstart, ranking
from (select code, numb, taxi_name,dstart,
             rank() over (partition by code, numb order by dstart desc) as ranking
      from detail
     ) d join
     (select r.*,
             rank() over (partition by code, numb order by rstart desc) as ranking
      from requirement
     ) r
     on d.code = r.code and
        d.ranking = 1 and
        r.ranking = 1
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