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Home/ Questions/Q 6671367
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Editorial Team
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Editorial Team
Asked: May 26, 20262026-05-26T03:22:48+00:00 2026-05-26T03:22:48+00:00

>>> os.path.realpath(C:) ‘C:\\PythonApp’ >>> os.path.realpath(E:) ‘E:\\’ My current directory is C:\PythonApp . It seems

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>>> os.path.realpath("C:")
'C:\\PythonApp'
>>> os.path.realpath("E:")
'E:\\'

My current directory is C:\PythonApp. It seems os defaults to the current directory if I give it an unknown path name for something like os.listdir so why does it work for E and not C?

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  1. Editorial Team
    Editorial Team
    2026-05-26T03:22:49+00:00Added an answer on May 26, 2026 at 3:22 am

    Compare what you get with:

     os.path.realpath("C:\\")
    

    Windows saves a “current directory” for each drive, and C: (without the slash) refers to that, not the root of the drive.
    The python docs for os.path.join mention this:

    Note that on Windows, since there is a current directory for each drive, os.path.join(“c:”, “foo”) represents a path relative to the current directory on drive C: (c:foo), not c:\foo.

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