Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • Home
  • SEARCH
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 5942695
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: May 22, 20262026-05-22T16:17:24+00:00 2026-05-22T16:17:24+00:00

Otherwise, it needs to be h = {:a => 1, :b => 2.2} h.each_with_index

  • 0

Otherwise, it needs to be

h = {:a => 1, :b => 2.2}
h.each_with_index do |pair, i|
  k = pair[0]; v = pair[1]
  p k, v, i
end

and setting the k and v this way seems a bit clumsy. Can it be simpler or something like

h.each_with_index do |[k,v], i|

?

  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-05-22T16:17:25+00:00Added an answer on May 22, 2026 at 4:17 pm

    In fact, yes! Use parentheses:

    h = {:a => 1, :b => 2.2}
    h.each_with_index do |(k, v), i|
      p k, v, i
    end
    
    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

I am developing an app that needs to match people together. Each person can
Can you please let me know on the quickest and efficient way to compare
I have an Ajax call that currently needs to be synchronous. However, while this
I would like to implement undo/redo in a small paint application . It seems
Let's say I have a property on a class that needs to be rendered
I’ve two individual pages which actual needs the same kind of function so I’ll
I'm busy with a form that needs to have an option to duplicate certain
I think at this point I've just looked at this code so long that
There are 2 reports that are produced at the end of each day. I
I need a shuffle albums algorithm for my audio player like in foobar2k. So

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.