Our application is using initialization code that depends on the order static code is executed and I’m wondering if this order will be consistent across all JVMs.
Here is a sample of what I mean:
public class Main {
static String staticVar = "init_value";
public static void main(String[] args) {
System.out.println(A.staticVar);
staticVar = "mainValue";
System.out.println(A.staticVar);
}
}
public class A {
static String staticVar = Main.staticVar;
}
will give:
init_value init_value
and
public class Main {
static String staticVar = "init_value";
public static void main(String[] args) {
// System.out.println(A.staticVar);
staticVar = "mainValue";
System.out.println(A.staticVar);
}
}
public class A {
static String staticVar = Main.staticVar;
}
will give (on my environment):
mainValue
To summarize, across all JVMs, is static code always executed when we use a class for the first time?
EDIT: Despite all the reassurances below, if you’re thinking of relying on this sort of thing, I would try hard to refactor your code so that it doesn’t crop up. While it is guaranteed to work, it’s also likely to make your code very brittle. The fact that static initializers get called “invisibly” makes them relatively hard to reason about and debug.
Yes, this is guaranteed by the language specification. From section 8.7 of the spec:
And from section 12.4: