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Home/ Questions/Q 1067127
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Editorial Team
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Editorial Team
Asked: May 16, 20262026-05-16T20:06:57+00:00 2026-05-16T20:06:57+00:00

package { import flash.display.Sprite; public class test1 extends Sprite { private var tmp:Object; public

  • 0
package {
    import flash.display.Sprite;

public class test1 extends Sprite {

private var tmp:Object;

public function test1() {
  createObj(tmp);
  if(tmp == null) {
    trace("nothing changed");
  }
}

private function createObj(obj:Object):void {
  obj = new Object();
}

}
}

In the above code the output on the console is :
nothing changed

Why?

If the argument to createObj was passed by reference(which is the
default behavior of actionscript), why did it not get modified?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-16T20:06:58+00:00Added an answer on May 16, 2026 at 8:06 pm

    You don’t pass a reference. You are passing null which is assigned to the local variable obj for use within the function.

    Passing arguments by value or by reference:

    To be passed by reference means that
    only a reference to the argument is
    passed instead of the actual value. No
    copy of the actual argument is made.
    Instead, a reference to the variable
    passed as an argument is created and
    assigned to a local variable for use
    within the function.

    In createObj you are creating a new reference which you must return:

    public function test1() {
      tmp = createObj();
      if(tmp != null) {
        trace("Hello World!");
      }
    }
    
    private function createObj():Object {
      return new Object();
    }
    
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