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Editorial Team
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Editorial Team
Asked: May 21, 20262026-05-21T15:48:50+00:00 2026-05-21T15:48:50+00:00

Pardon my newbie-ness to Java as I am not experienced enough to know the

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Pardon my newbie-ness to Java as I am not experienced enough to know the most efficient way to do this. I have a hashmap like below, but it would have like 40,000 entries:

Map <String, String> someHashmap = new HashMap <String, String> ();
someHashmap.put("filepath1", null);
someHashmap.put("filepath2", "tag1");
someHashmap.put("filepath3", "tag2");

I want to determine how many value match null so that I can determine if any are null. Of course I could do a regular loop to check but am wondering if there is a more efficient way, thanks

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  1. Editorial Team
    Editorial Team
    2026-05-21T15:48:50+00:00Added an answer on May 21, 2026 at 3:48 pm

    You can use the containsValue method, which states:

    Returns true if this map maps one or
    more keys to the specified value.

    somHashmap.containsValue(null);
    

    However keep in mind, that if you have a large dataset(and it seems you do), you should create a separate data structure to keep track of the values that allow for O(1) lookup time, rather than O(n) time, as suggested in other answers.

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