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Home/ Questions/Q 7956549
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Editorial Team
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Editorial Team
Asked: June 4, 20262026-06-04T04:01:44+00:00 2026-06-04T04:01:44+00:00

PART 1: I need to create a loop for a set of array variables

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PART 1: I need to create a loop for a set of array variables

for ($cnt=1; $cnt<=$qty; $cnt++) {
      $firstvar.$cnt['Code'] = '02';
      $secondvar.$cnt['Type'] = $somevar;
      $thirdvar.$cnt['Code'] = 'IN';
   }

// with a result of

      $firstvar1['Code'] = '02';
      $secondvar1['Type'] = $somevar;
      $thirdvar1['Code'] = 'IN';

      $firstvar2['Code'] = '02';
      $secondvar2['Type'] = $somevar;
      $thirdvar2['Code'] = 'IN';  

//etc.

However, the parsing of the $cnt variable seems to be conflicting with the array.

PART 2: I then need to create an array of variables like so:

  $lastvar['Thing'] = array( $thirdvar1, $thirdvar2, ... $thirdvar.$qty );

Here, creating a simple string using a for loop and placing it in the array doesn’t work.

THANKS!

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-04T04:01:50+00:00Added an answer on June 4, 2026 at 4:01 am

    PART 1: $firstvar.$cnt['Code'] should be ${"firstvar$cnt"}['Code'] (or ${'firstvar'.$cnt}['Code']).

    PART 2:

    for ($cnt=1; $cnt<=$qty; $cnt++) {
        $lastvar['Thing'][] = ${'thirdvar'.$qty};
    }
    

    PART 3: (mine!)
    Put everything in the same loop:

    for ($cnt=1; $cnt<=$qty; $cnt++) {
      ${'firstvar'.$cnt}['Code']  = 02;
      ${'secondvar'.$cnt}['Type'] = $somevar;
      ${'thirdvar'.$cnt}['Code']  = 'IN';
      $lastvar['Thing'][]         = ${thirdvar$qty};
    

    }

    Keep in mind that this code would be cleaner if you use arrays instead of variables names concatenation.

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