Question

pathString="E:\new folder\Study\Batch\test_project_nuke\test_render\testImg_###.jpeg"

I tried to first separate the extension and found presence of \t converts string \t tab .

also I tried this way

numberOfSplChar=pathString.rfind("#") - pathString.find("#")
print numberOfSplChar

and found 1 less..

Answer 1

pathString="E:\new folder\Study\Batch\test_project_nuke\test_render\testImg_###.jpeg"

I tried to first separate the extension and found presence of \t
converts string \t tab .

That’s one issue: a "\t" in a string literal means a tab. You either should write \\t or put it in a raw string (r"\t").

also i tried this way

numberOfSplChar=pathString.rfind("#") - pathString.find("#")
print numberOfSplChar

and found 1 less..

Of course. Let’s take this simpler string:

pathString = "a###b".

rfind() gives 3, lfind gives 1. The difference is the distance from the 1st to the last, which is one less than the number. So just add 1.

But beware of strings like 'a###b###c###d###e' – how should they be treated?