Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • SEARCH
  • Home
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 6785275
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: May 26, 20262026-05-26T17:06:25+00:00 2026-05-26T17:06:25+00:00

per my question Aes Encryption… missing an important piece , I have now learned

  • 0

per my question Aes Encryption… missing an important piece, I have now learned that my assumption for creating a reversible encryption on a string was a bit off. I now have

    public static byte[] EncryptString(string toEncrypt, byte[] encryptionKey)
    {
        var toEncryptBytes = Encoding.UTF8.GetBytes(toEncrypt);
        using (var provider = new AesCryptoServiceProvider())
        {
            provider.Key = encryptionKey;
            provider.Mode = CipherMode.CBC;
            provider.Padding = PaddingMode.PKCS7;
            using (var encryptor = provider.CreateEncryptor(provider.Key, provider.IV))
            {
                using (var ms = new MemoryStream())
                {
                    using (var cs = new CryptoStream(ms, encryptor, CryptoStreamMode.Write))
                    {
                        cs.Write(toEncryptBytes, 0, toEncryptBytes.Length);
                        cs.FlushFinalBlock();
                    }
                    return ms.ToArray();
                }
            }
        }
    }

and this produces consistent results; however, I will not be able to decrypt without knowing/ setting the initialization vector. I really do not want to pass three values into this method (on for the IV), which leaves me with hardcoding the IV or deriving it from the key. I’d like to know if this is a good practice, or if it will render the encrypted value vulnerable to attack somehow… or am I really overthinking this and should just hardcode the IV?

UPDATE
Per Iridium’s suggestion, I tried something like this instead:

    public static byte[] EncryptString(string toEncrypt, byte[] encryptionKey)
    {
        if (string.IsNullOrEmpty(toEncrypt)) throw new ArgumentException("toEncrypt");
        if (encryptionKey == null || encryptionKey.Length == 0) throw new ArgumentException("encryptionKey");
        var toEncryptBytes = Encoding.UTF8.GetBytes(toEncrypt);
        using (var provider = new AesCryptoServiceProvider())
        {
            provider.Key = encryptionKey;
            provider.Mode = CipherMode.CBC;
            provider.Padding = PaddingMode.PKCS7;
            using (var encryptor = provider.CreateEncryptor(provider.Key, provider.IV))
            {
                using (var ms = new MemoryStream())
                {
                    ms.Write(provider.IV, 0, 16);
                    using (var cs = new CryptoStream(ms, encryptor, CryptoStreamMode.Write))
                    {
                        cs.Write(toEncryptBytes, 0, toEncryptBytes.Length);
                        cs.FlushFinalBlock();
                    }
                    return ms.ToArray();
                }
            }
        }
    }

    public static string DecryptString(byte[] encryptedString, byte[] encryptionKey)
    {
        using (var provider = new AesCryptoServiceProvider())
        {
            provider.Key = encryptionKey;
            provider.Mode = CipherMode.CBC;
            provider.Padding = PaddingMode.PKCS7;
            using (var ms = new MemoryStream(encryptedString))
            {
                byte[] buffer;
                ms.Read(buffer, 0, 16);
                provider.IV = buffer;
                using (var decryptor = provider.CreateDecryptor(provider.Key, provider.IV))
                {
                    using (var cs = new CryptoStream(ms, decryptor, CryptoStreamMode.Read))
                    {
                        byte[] decrypted = new byte[encryptedString.Length];
                        var byteCount = cs.Read(decrypted, 0, encryptedString.Length);
                        return Encoding.UTF8.GetString(decrypted, 0, byteCount);
                    }
                }
            }
        }
    }

however, this shows something odd in my unit test:

    [TestMethod]
    public void EncryptionClosedLoopTest()
    {
        var roundtrip = "This is the data I am encrypting.  There are many like it but this is my encryption.";
        var encrypted = Encryption.EncryptString(roundtrip, encryptionKey);
        var decrypted = Encryption.DecryptString(encrypted, encryptionKey);
        Assert.IsTrue(roundtrip == decrypted);
    }

my decrypted text shows up as “92ʪ�F”�,hpv0�� I am encrypting. There are many like it but this is my encryption.” which seems almost right but of course completely wrong. It looks like I’m close though. Am I missing an offset on the memory stream?

  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-05-26T17:06:26+00:00Added an answer on May 26, 2026 at 5:06 pm

    The IV should be random and unique for every run of your encryption method. Deriving it from the key/message or hard-coding it is not sufficiently secure. The IV can be generated within this method, instead of passed into it, and written to the output stream prior to the encrypted data.

    When decrypting, the IV can then be read from the input before the encrypted data.

    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

As per Shanes excellent solution of another question, I now realise that I do
Per a great answer from another question I have begun mounting global resources (css/js/images)
As per the title I have three parts to this question... Is db4o object
As per question how to i create a a file that also includes the
This isn't actually a homework question per se, just a question that keeps nagging
As per question. So I have a main window (MainForm) load when application start.
As per another question I had asked earlier I think I may have found
This is not a programming question per se but a question that may be
As per my previous question , I have a working animation which fades in
Per this question (see comments near the bottom), I was wondering if anyone knows

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.