Question

<?php
class Page {
    function getPage($urlOfPage){
        $result = mysql_query('SELECT category, title FROM rs-planet WHERE url = "'.  mysql_real_escape_string($urlOfPage));
        if(mysql_num_rows($result) === 0){
            header('HTTP/1.0 404 Not Found');
            exit;
        }
        else{
            return $page[] = mysql_fetch_array($result);
        }
    }
}

?>

And I have this errors:

Warning: mysql_num_rows() expects parameter 1 to be resource, boolean
given in C:\xampp\htdocs\rs-planet\classes\page.php on line 6

Warning: mysql_fetch_array() expects parameter 1 to be resource,
boolean given in C:\xampp\htdocs\rs-planet\classes\page.php on line 11
And I don’t see the problem…

And if I do var_dump @ $result I get a boolean. (If it’s founded @ the db it gives true, if it isn’t it gives me false.)

PS. Sorry for my bad English, my main language is Dutch.

EDIT:
var_dump(mysql_error) =

string(152) “You have an error in your SQL syntax; check the manual
that corresponds to your MySQL server version for the right syntax to
use near ‘”index’ at line 1”

Answer 1

mysql_query returns false if the query cannot be executed (i.e. bad syntax). Try surrounding rs-planet with backticks:

$result = mysql_query('SELECT category, title FROM `rs-planet` WHERE url = "'.  mysql_real_escape_string($urlOfPage) . '"');

I’m thinking the - in the table name is screwing up the syntax.

EDIT: Also, PDO makes it much easier to debug these issues since you don’t need to use mysql_error() to get the error message – it’s included in the Exception thrown by PDO.
http://php.net/manual/en/book.pdo.php

SECOND EDIT: Actually the problem is likely the missing quote. Fixed my code, but see the other answers…