Question

<?php
echo $this->Form->button('A Button');
echo $this->Form->button('Another Button', array('type'=>'button'));
echo $this->Form->button('Reset the Form', array('type'=>'reset'));
echo $this->Form->button('Submit Form', array('type'=>'submit'));
?>

Which should i use among them?

I will click a button and the jquery ajax code will be executed.

The whole page will not be reloaded/refreshed.

Only the part of that division will be reloaded and the result getting from database will be displayed .

I have added a division , it’s for Poll.

There is a question and four answers.

One can select one radio button and click the button then the result from database will be displayed in that division.

How can i do this with jQuery ajax ?

The jQuery ajax format is like that =>

$.ajax({
   type: "POST",
   url: "some.php",
   data: "name=John&location=Boston",
   success: function(msg){
     alert( "Data Saved: " + msg );
   }
 });

So how can i call an action of a controller with this format ?

Thanks in advance.

Answer 1

If you don’t want to reload the page, then go with one of these:

echo $this->Form->button('A Button');
echo $this->Form->button('Another Button', array('type'=>'button'));