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Home/ Questions/Q 6559899
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Editorial Team
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Editorial Team
Asked: May 25, 20262026-05-25T13:23:26+00:00 2026-05-25T13:23:26+00:00

<?php $error = ‘error’; $check = $_SERVER[‘REQUEST_URI’]; if($check == /bleachers.php) { echo ‘bleachers’; }

  • 0
<?php
$error = 'error';
$check = $_SERVER['REQUEST_URI'];
if($check == "/bleachers.php") 
{
    echo 'bleachers';
} 
elseif($check == 'runners.php') 
{ 
    echo 'runners'; 
}
else
{ 
    echo $error;
}
?>

I’m trying to figure out why this is not working. I am trying to echo out a text based on the url of a website. If the url is site.com/bleachers.php echo bleachers
elseif site.com/runners.php echo runners else echo error.

I type in the url site.com/bleachers and error prints out instead.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-25T13:23:26+00:00Added an answer on May 25, 2026 at 1:23 pm

    Start with changing:

    else echo $error;
    

    into:

    else echo $_SERVER['REQUEST_URI'];
    

    this should help you determine what should actually be in the if statements.

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