Question

<?php
function filter($fst, $arr){
$new_arr=array();

    for($i=0;$i<=(count($arr)-1);$i++){
        if(substr($arr[$i], 0, 1) == $fst){
            $new_arr[] = $fst;
        }
    }
    return $new_arr;
}



$list = Array("Apparel","Associations","Building/Grounds","Building/Materials",
              "Dispensing","Disposables","Distributors");

$new_list[]=filter("A", $list);

for($i=0;$i<=(count($new_list)-1);$i++){ 
    echo '<li><a href="?id='.$i.'">'.$new_list[$i].'</a></li>'; 
}

?>

I have created a function named filter() to filter the contents of an array that starts with a character like “a”. It does not work at the moment.

Answer 1

First of all I assume that you want to print the word that was OK and not the character you was checking with? $new_arr[] = $fst; should be $new_arr[] = $arr[$i];

Secondly you’re adding the resulting array of the function into a new array instead of assigning the array to your variable. $new_list[] = should be $new_list =.

Here’s an updated version of your code. I’ve marked where I’ve made changes..

function filter($fst, $arr){
$new_arr=array();

    for($i=0;$i<=(count($arr)-1);$i++){
        if(substr($arr[$i], 0, 1) == $fst){
            $new_arr[] = $arr[$i];         <----- Changed here
        }
    }
    return $new_arr;
}



$list = Array("Apparel","Associations","Building/Grounds","Building/Materials",
              "Dispensing","Disposables","Distributors");

$new_list=filter("A", $list);  <----- And changed here

for($i=0;$i<=(count($new_list)-1);$i++){ 
    echo '<li><a href="?id='.$i.'">'.$new_list[$i].'</a></li>'; 
}

Output:

<li><a href="?id=0">Apparel</a></li>
<li><a href="?id=1">Associations</a></li>