Question

<?php

include 'db.php';

$subassetcategory = $_GET["subassetcategory"];

if ($subassetcategory == "all") {
    $sql = "SELECT * FROM asset_subasset";
}
else {
    $sql = "SELECT * FROM asset_subasset WHERE subassetcategory = '" . $subassetcategory . "'";
}

$result = mysql_query($sql) or die(mysql_error());

if ($row = mysql_fetch_array($result)) {

    echo "<table border='1'>
            <tr>
            <th>Asset ID</th>
            <th>Subasset Category</th>
            <th>Subasset Name</th>
            </tr>";

    while ($row = mysql_fetch_array($result)) {
        $subassetid = $row['subassetid'];
        $assetid = $row['assetid'];
        $subassetname = $row['subassetname'];
        $subassetcategory = $row['subassetcategory'];

        echo "<tr>";
        echo "<td>" . $assetid . "</td>";
        echo "<td>" . $subassetcategory . "</td>";
        echo "<td>" . $subassetname . "</td>";
        echo "<td>" . "<a href='viewassetdetail.php?subassetid=$subassetid&assetid=$assetid'>View<a/>" . "</td>";
        echo "</tr>";
    }
    echo "</table>";
}
else {
    echo "<br> No data found </br>";
}

mysql_close($connect);

?>

Please help me, I couldn’t figure out as to why this code cannot return the result properly. It returned less 1 row (if result suppose to have 2 rows it will only return 1) from the exact rows available in the database.

if ($row = mysql_fetch_array($result)) {

    echo "<table border='1'>
            <tr>
            <th>Asset ID</th>
            <th>Subasset Category</th>
            <th>Subasset Name</th>
            </tr>";

    while ($row = mysql_fetch_array($result)) {
        $subassetid = $row['subassetid'];
        $assetid = $row['assetid'];
        $subassetname = $row['subassetname'];
        $subassetcategory = $row['subassetcategory'];

        echo "<tr>";
        echo "<td>" . $assetid . "</td>";
        echo "<td>" . $subassetcategory . "</td>";
        echo "<td>" . $subassetname . "</td>";
        echo "<td>" . "<a href='viewassetdetail.php?subassetid=$subassetid&assetid=$assetid'>View<a/>" . "</td>";
        echo "</tr>";
    }
    echo "</table>";
}
else {
    echo "<br> No data found </br>";
}

mysql_close($connect);

?>

if I just wrote this code, it works perfectly.

$result = mysql_query($sql) or die(mysql_error());

echo "<table border='1'>
    <tr>
    <th>Asset ID</th>
    <th>Subasset Category</th>
    <th>Subasset Name</th>
    </tr>";

while ($row = mysql_fetch_array($result)) {
    $subassetid = $row['subassetid'];
    $assetid = $row['assetid'];
    $subassetname = $row['subassetname'];
    $subassetcategory = $row['subassetcategory'];

    echo "<tr>";
    echo "<td>" . $assetid . "</td>";
    echo "<td>" . $subassetcategory . "</td>";
    echo "<td>" . $subassetname . "</td>";
    echo "<td>" . "<a href='viewassetdetail.php?subassetid=$subassetid&assetid=$assetid'>View<a/>" . "</td>";
    echo "</tr>";
}
echo "</table>";

mysql_close($connect);

?>

But I want it to show “No data found” if the result was empty. So, any help? I know it’s very simple but I couldn’t find the answer for days already. Thank you in advance!

Answer 1

You are basically slicing off the first result in your if statement:

if ($row = mysql_fetch_array($result))

Just check for the number of rows returned to keep the resultset intact:

if(mysql_num_rows($result) > 0)