Question

 <?php
$ip = htmlspecialchars($_GET["ip"]);
$serverIp = "a";
$a = "a";
include("mysql.php"); 
$votes = "serverVotes";
$results = mysql_query("SELECT * FROM toplist WHERE serverIp = $_POST[serverIp] ORDER BY $votes DESC");

  if($row['serverIp'] = $_POST[serverIp]) {
        echo 'Yes1.'; //debugging
}
  if($row['serverIp'] != $_POST[serverIp]) {
        echo 'No1.'; //debugging
}

    while($row = mysql_fetch_array($results)){

  if($row['serverIp'] = $_POST[serverIp]) {
        echo 'Yes2.'; //debugging
}
  if($row['serverIp'] != $_POST[serverIp]) {
        echo 'No2.'; //debugging
}

    }
?>

I’m trying to make it, so that if “serverIp” exists in the database, it will echo certain information, and if it doesn’t exists, it will just do nothing. I don’t think it is
actually getting the IP from the form, but I may be wrong, it may be some other problem.

Answer 1

have you tried this?

$ip = htmlspecialchars($_GET["ip"]);
$serverIp = "a";
$a = "a";
include("mysql.php"); 
$votes = "serverVotes";
$results = mysql_query("SELECT * FROM toplist WHERE serverIp = '".$_POST['serverIp']."' ORDER BY $votes DESC");
$row = mysql_fetch_array($results);

  if($row['serverIp'] === $_POST['serverIp']) {
        echo 'Yes1.'; //debugging
}
  if($row['serverIp'] != $_POST['serverIp']) {
        echo 'No1.'; //debugging
}

    while($row = mysql_fetch_array($results)){

  if($row['serverIp'] === $_POST['serverIp']) {
        echo 'Yes2.'; //debugging
}
  if($row['serverIp'] != $_POST['serverIp']) {
        echo 'No2.'; //debugging
}

    }