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Home/ Questions/Q 6163509
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Editorial Team
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Editorial Team
Asked: May 23, 20262026-05-23T21:50:14+00:00 2026-05-23T21:50:14+00:00

<?php $offset = 0; $find = is; $find_length = strlen($find); $string = This is

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<?php

$offset = 0;
$find = "is";
$find_length = strlen($find);
$string = "This is a string, and it is an example.";

while($string_position = strpos($string, $find, $offset)){

echo $find. " Found at ". $string_position ."<br>";
$offset = string_position + find_length;

}


?>

keeping getting “is Found at 2″ over and over . i am expecting ” is found at 2″, then 5, then 25

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  1. Editorial Team
    Editorial Team
    2026-05-23T21:50:15+00:00Added an answer on May 23, 2026 at 9:50 pm
    $offset = string_position + find_length;
    

    Use variables instead of constants

    $offset = $string_position + $find_length;
    

    If the needle is found at the beginning of the string, strpos() returns 0, which means, that the loop will never start.

    while(($string_position = strpos($string, $find, $offset)) !== false) {
      // code
    }
    

    Additional change your error settings in your development environment

    error_reporting(E_ALL | E_STRICT);
    

    Now you will get this as notice

    PHP Notice:  Use of undefined constant string_position - assumed 'string_position' in php > shell code on line 4
    PHP Stack trace:
    PHP   1. {main}() php shell code:0
    
    Notice: Use of undefined constant string_position - assumed 'string_position' in php shell > code on line 4
    
    Call Stack:
        1.2172     636208   1. {main}() php shell code:0
    
    PHP Notice:  Use of undefined constant find_length - assumed 'find_length' in php shell code on line 4
    PHP Stack trace:
    PHP   1. {main}() php shell code:0
    
    Notice: Use of undefined constant find_length - assumed 'find_length' in php shell code on line 4
    
    Call Stack:
        1.2172     636208   1. {main}() php shell code:0
    
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