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Home/ Questions/Q 903507
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Editorial Team
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Editorial Team
Asked: May 15, 20262026-05-15T15:53:28+00:00 2026-05-15T15:53:28+00:00

<?php $server = $_SERVER[SERVER_NAME]; $pathpath = realpath(../../files/uploaded_file.jpg); echo You can link to the file

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<?php
    $server = $_SERVER["SERVER_NAME"];
    $pathpath = realpath("../../files/uploaded_file.jpg");
    echo "You can link to the file using the following link... $server$pathpath";
?>

Unfortunately this produces the following…

www.example.com/home/fhlinux123/g/example.com/user/htdocs/ninja/base/files/1.doc

Whereas what I am after is as follows…

www.example.com/files/uploaded_file.jpg

I can’t assume that the folder ‘files’ will always be in the same directory.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-15T15:53:29+00:00Added an answer on May 15, 2026 at 3:53 pm

    That’s because realpath returns the absolute path from the server box root, not the webserver htdocs root.
    You can retrieve the webserver htdocs root from $_SERVER[“DOCUMENT_ROOT”], then strip that from the beginning of the result returned by realpath

    Quick and dirty example:

    $server = $_SERVER["SERVER_NAME"]; 
    $pathpath = realpath("../../files/uploaded_file.jpg"); 
    $serverPath = $_SERVER["DOCUMENT_ROOT"];
    $pathpath = substr($pathpath,strlen($serverPath));
    
    echo "You can link to the file using the following link... $server$pathpath"; 
    
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