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Editorial Team
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Asked: 2026-06-05T22:44:31+00:00

<?php $user = substr(md5(rand()),0,16); $pass = substr(md5(rand()),0,20); $query = CREATE USER ‘{$user}’@’%’ IDENTIFIED BY

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<?php
$user = substr(md5(rand()),0,16);
$pass = substr(md5(rand()),0,20);
$query = "CREATE USER '{$user}'@'%' IDENTIFIED BY '{$pass}'; 
GRANT USAGE ON * . * TO '{$user}'@'%' IDENTIFIED BY '{$pass}' WITH MAX_QUERIES_PER_HOUR 0 MAX_CONNECTIONS_PER_HOUR 0 MAX_UPDATES_PER_HOUR 0 MAX_USER_CONNECTIONS 0; 
CREATE DATABASE IF NOT EXISTS `{$user}`; 
GRANT ALL PRIVILEGES ON `{$user}` . * TO '{$user}'@'%';";
mysql_connect("***.****.info", "***", "****") or die(mysql_error());
mysql_query($query) or die(mysql_error());
?>

You have an error in your SQL syntax; check the manual that
corresponds to your MySQL server version for the right syntax to use
near ‘GRANT USAGE ON *.* TO ’78eb50407b017587’@’%’ IDENTIFIED BY
‘4fa70f7cc25ccf9dc9dd’ at line 1.

Anyone know what’s going on here

Update I removed identified by and it did nothing. Any other suggestions?

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1 Answer

  1. Editorial Team

    mysql_query() doesn’t support multiple query. Do the query one by one.

    mysql_connect("***.****.info", "***", "****") or die(mysql_error());
$query1 = "CREATE USER '{$user}'@'%' IDENTIFIED BY '{$pass}';";
$query2 = "GRANT USAGE ON * . * TO '{$user}'@'%' IDENTIFIED BY '{$pass}' WITH MAX_QUERIES_PER_HOUR 0 MAX_CONNECTIONS_PER_HOUR 0 MAX_UPDATES_PER_HOUR 0 MAX_USER_CONNECTIONS 0;";
$query3 = "CREATE DATABASE IF NOT EXISTS `{$user}`;";
$query4 = "GRANT ALL PRIVILEGES ON `{$user}` . * TO '{$user}'@'%';";
mysql_query($query1) or die(mysql_error());
mysql_query($query2) or die(mysql_error());
mysql_query($query3) or die(mysql_error());
mysql_query($query4) or die(mysql_error());

    But, given the structure of your query, I would suggest you to do a transactions query. You can read more about it, here:

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