Question

Please check the below code,

import sys
try:
    seq=eval(raw_input("Enter seq number: "))
    if seq <= 0 or seq >= 9999:
       print "Sequence number not in range [0001-9999]"
       sys.exit(1)
except:
      print "!!! Sequence number not in range [0001-9999]"
      sys.exit(1)

I gave a string to eval raw_input function.

$> python test.py
Enter seq number: "12"


Sequence number not in range [0001-9999]
!!! Sequence number not in range [0001-9999]

Why is it not exiting even after receiving exit call?

Answer 1

sys.exit just raises an exception (SystemExit), which is then caught. As a demonstration:

import sys
import traceback

try:
    sys.exit(1)
except:
    print "This threw the following exception:"
    traceback.print_exc()
# This threw the following exception:
# Traceback (most recent call last):
#   File "test.py", line 5, in <module>
#     sys.exit(1)
# SystemExit: 1