Question

please check with me where is the error in this ajax code to send 2 parameters:

var xhr = getXhr();
// On défini ce qu'on va faire quand on aura la réponse
xhr.onreadystatechange = function(){
    // On ne fait quelque chose que si on a tout reçu et que le serveur est ok
    if(xhr.readyState == 4 && xhr.status == 200)
        {
        selects = xhr.responseText;
        // On se sert de innerHTML pour rajouter les options a la liste
        //document.getElementById('prjsel').innerHTML = selects;
        }
        };
        xhr.open("POST","ServletEdition",true);
          xhr.setRequestHeader('Content-Type','application/x-www-form-urlencoded');
          id=document.getElementById(idIdden).value;
          fu=document.getElementById("formUpdate").value;
          //alert(fu);
          var i=1;
          xhr.send("id=" +id+", fu="+i);

i cant got the value of fu i don’t know why.
thanks

Answer 1

The contents of your xhr.send() need to be URL encoded. For example:

xhr.send("id=1&fu=2");

Basicallly, anything that goes inside the xhr.send() would be the same as the query string you’d set with a GET. In other words, what you have inside send should also work on the end of a URL:

http://www.mysite.com/path/to/script?id=1&fu=2