Question

Please consider the following Code:

#include <stdio.h>

int main()
{
    int x;
    printf ("\nEnter x: ");
    scanf ("%d", &x);

    return x;
}

Output:
$Enter x: -2

$echo $?
254

My Question is:

The OS knows that return value of main() by executing a process P (The above code under execution) is NON-ZERO.

Does the OS does any kind of Handling in such cases?

Answer 1

It has to be made clear what you are understanding by the “operating system” here.

If you look from the shell’s point of view (which usually is just another userspace program anyway, and not a part of the kernel itself), the exit value of a process is used to evaluate the value of an expression and is important when doing shell programming as it is the most natural check one does after the termination of a process.

From the point of view of the kernel, the exit value of a process is largely dismissed. The kernel has to clean after the process regardless of the exit code it has returned.