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Home/ Questions/Q 3271904
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Editorial Team
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Editorial Team
Asked: May 17, 20262026-05-17T18:46:24+00:00 2026-05-17T18:46:24+00:00

Please consider the following table ‘mmm’: select * from mmm; Output: +——-+——-+——+ | texto

  • 0

Please consider the following table ‘mmm’:

select * from mmm;

Output:

+-------+-------+------+  
| texto | value | n    |  
+-------+-------+------+  
| aaa   |    10 | 1    |  
| aab   |    10 | 1    |  
| aaa   |    11 | 1    |  
| aab   |    11 | 1    |  
| aaa   |    10 | 2    |  
+-------+-------+------+  

The command:

select a.*, '--', b.* 
  from mmm a 
left join mmm b on (a.n=b.n) 
where  a.value < b.value 
  and a.texto ='aaa' 
  and b.texto='aab';

returns:

+-------+-------+------+----+-------+-------+------+  
| texto | value | n    | -- | texto | value | n    |  
+-------+-------+------+----+-------+-------+------+  
| aaa   |    10 | 1    | -- | aab   |    11 | 1    |  
+-------+-------+------+----+-------+-------+------+  

That’s fine. But what I want is something like:

+-------+-------+------+----+-------+-------+------+  
| texto | value | n    | -- | texto | value | n    |  
+-------+-------+------+----+-------+-------+------+  
| aaa   |    10 | 1    | -- | aab   |    11 | 1    |  
+-------+-------+------+----+-------+-------+------+  
| aaa   |    10 | 2    | -- | NULL  |  NULL | NULL |  
+-------+-------+------+----+-------+-------+------+  
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-17T18:46:24+00:00Added an answer on May 17, 2026 at 6:46 pm
    select a.*, '--', b.* 
      from mmm a 
    left join mmm b on (a.n=b.n) 
    where  (a.value < b.value or b.value is null)
      and a.texto ='aaa' 
      and (b.texto='aab' or b.textto is null);
    

    or:

    select a.*, '--', b.* 
      from mmm a 
    left join mmm b on (a.n=b.n and a.value < b.value and b.texto = 'aab') 
    where a.texto ='aaa' ;
    
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