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Asked: 2026-05-28T00:18:58+00:00

Please consider the following URLs: http://www.mydomain.com/a/test.php https://www.mydomain.org/a/b/test.php http://www.mydomain.co.nr/a/b/c/test.php https://www.mydomain.com/a/b/c/d/test.php http://www.mydomain.co.uk/a/b/c/d/e/test.php https://www.mydomain.co.au.nm/a/b/c/d/e/f/test.php?var1=test1&var2=test2 Now I want

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Please consider the following URLs:

http://www.mydomain.com/a/test.php
https://www.mydomain.org/a/b/test.php
http://www.mydomain.co.nr/a/b/c/test.php
https://www.mydomain.com/a/b/c/d/test.php
http://www.mydomain.co.uk/a/b/c/d/e/test.php
https://www.mydomain.co.au.nm/a/b/c/d/e/f/test.php?var1=test1&var2=test2

Now I want to declare a constant called ACTUAL_URL in test.php file so that it contains the following outputs respectively (Lets assume that these URLs represent the main directory of the website, respectively in the order mentioned above):

http://www.mydomain.com/
https://www.mydomain.org/a/
http://www.mydomain.co.nr/a/b/
https://www.mydomain.com/a/b/c/
http://www.mydomain.co.uk/a/b/c/d/
https://www.mydomain.co.au.nm/a/b/c/d/e/

Now consider a file, 1.php located in the following locations:

http://www.mydomain.com/1.php
https://www.mydomain.org/a/1.php
http://www.mydomain.co.nr/a/b/1.php
https://www.mydomain.com/a/b/c/1.php
http://www.mydomain.co.uk/a/b/c/d/1.php
https://www.mydomain.co.au.nm/a/b/c/d/e/1.php

The PHP code for 1.php would be:

//1.php
//The folder name may remain as "a" or may change. 
//But for most cases, it will be "a"
require_once('a/test.php');

//Rest of the code for the page

Few things to note:

  1. Ideally test.php will never be executed on its own. Rather, it is an include file that would be included in other files within the main directory and/or within any other files in the sub-directories.
  2. Note that the code is smart enough to detect http and https from the received url and use the same.
  3. It could be a .com domain or a .co.au.nm domain and it would still fetch it correctly.
  4. Strips out any parameters received via $_GET.

I tried the following, but failed to get a satisfactory answer:

define("ACTUAL_URL", basename($_SERVER['PHP_SELF']) );
define("ACTUAL_URL", dirname($_SERVER['PHP_SELF']) );
define("ACTUAL_URL", $_SERVER["SERVER_NAME"].$_SERVER["REQUEST_URI"] );

The first 2 dont provide the website URL, rather they seem to provide the physical path of the folder, which is not required. I need the accessible URL. The third one gives the domain name + folders (which is good) but contains the file name of the currently executing page and any $_GET params associated with it. For example, consider the following structure of my files in a website:

https://www.mydomain.co.au.nm/a/b/c/d/e/1.php?var1=test1&var2=test2
https://www.mydomain.co.au.nm/a/b/c/d/e/f/test.php

In the above case, I want the constant ACTUAL_URL to give me:

https://www.mydomain.co.au.nm/a/b/c/d/e/

Relative path to test.php will always be included in 1.php file.

So how can I achieve the above indicated functionality?

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1 Answer

  1. Editorial Team

    You can use the dirname() function twice. Once to get rid of the filename (and any querystring variables) and another time to traverse up one directory.

    dirname(dirname($_SERVER["REQUEST_URI"]));

    Please note, this won’t work on files in the root directory of the website. All your paths will need to be at least 1 folder deep.

    Really though, this whole approach is questionable from a security standpoint. Allowing the client to pass in paths which ultimately get chopped up and passed into require_once opens your application up to path traversal attacks. If you are going to do this, make sure to validate/sanitize the input.

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