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Home/ Questions/Q 6729437
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Editorial Team
  • 0
Editorial Team
Asked: May 26, 20262026-05-26T10:17:24+00:00 2026-05-26T10:17:24+00:00

please consider these files: p.h: #ifndef _p_h_ #define _p_h_ class p{ public: static void

  • 0

please consider these files:

p.h:

#ifndef _p_h_
#define _p_h_

class p{
public:    
    static void set_func(int(*)());

private:
    static int (*sf)();

};
#endif

p.cpp:

#include "p.h"
#include <cstdio>

int (p::*sf)() = NULL;    //defining the function pointer

void p::set_func(int(*f)()){
    sf = f;
}

main.cpp:

#include "p.h"
#include <iostream>

int function_x(){
        std::cout << "I'm function_x()" << std::endl;
        return 1234;
}

int main(){
        p::set_func(function_x);
}

when compiling, I get this:

$ g++ -o pp main.cpp p.cpp
/tmp/ccIs0M7r.o:p.cpp:(.text+0x7): undefined reference to `p::sf'
collect2: ld returned 1 exit status

but:

$ g++ -c -o pp p.cpp

compiles right.

What’s wrong with the code? I just can’t find where the problem is, please your help will be more than appreciated.

Thanks.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-26T10:17:24+00:00Added an answer on May 26, 2026 at 10:17 am

    Your attempt at defining p::sf is incorrect – yours is a definition of a global variable named sf that is of type int (p::*)(), i.e. a pointer to a member function. Consequently p::sf remains undefined, hence the linker error.

    Try this instead:

    int (*p::sf)() = 0;
    
    // or,
    
    typedef int (*p_sf_t)();
    p_sf_t p::sf = 0;
    
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