Question

Please excuse my newbie Question.

I’m tryin to display data from a mysql table into a chart (phpChart http://phpchart.net)
What I need is to display all values of Field cost for Region ‘CA’

E.g

ID  Cost  Region
----------
1   500    CA
----------
2   100    DP
----------
3   280    CA
----------
4   40     ST
----------
5   80     CA
----------

<?php
include 'config.php';
$query = "SELECT Cost From tblForecast where Region='CA' =";
$rs = mysql_query($query);

if (!$rs) {
    echo "Could not execute query: $query";
    trigger_error(mysql_error(), E_USER_ERROR); 
} else {
    echo "Query: $query executed\n";
} 

$nrows = mysql_num_rows($rs);

for ($i = 0; $i < $nrows; $i++) {
    $row = mysql_fetch_row($rs);
    echo $row[0];
    echo "<br/>";
}

$pc = new C_PhpChartX(array(array($row[0])),'basic_chart');
\\"This where i'm stuck as to how display the other values within the array"

$pc->set_title(array('text'=>'Basic Chart with Bar Renderer'));
$pc->set_series_default(array('renderer'=>'plugin::BarRenderer'));

$pc->draw();
mysql_close();

?>

I’m able to display the first rows value in the chart only.

Anyone’s help would be much appreciated
Thanks in advance

Answer 1

You’re continually fetching your query results into a single variable, and overwriting that data on each iteration of the loop.

Try this:

$data = array();
while ($row = mysql_fetch_array($rs)) {
   $data[] = $row[0];
}

$pc = new C_PhpChartX($data, 'basic_chart');

Plus, though this is most likely on a cut/paste type, you’ve got a syntax error in your query anyways:

$query = "SELECT Cost From tblForecast where Region='CA' =";
                                                         ^---syntax error