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Please explain the following piece of code..
printf("%c\n",0+'0'); --> returns 0
printf("%c\n",1+'0'); --> returns 1
printf("%c\n",0+'1'); --> returns 1
printf("%c\n",1+'1'); --> returns 2
Thanx.
Look at the ASCII table. ‘0’ has code 48. So ‘0’ + 1 yields 49, which is ‘1’. So every character is in fact an integer. You add another integer to it and then, because you specify “%c” in printf, you force it to consider it a character. He goes check his ASCII table and, after some deliberation he decides to print the output to the screen.