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Home/ Questions/Q 8844473
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Editorial Team
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Editorial Team
Asked: June 14, 20262026-06-14T11:29:46+00:00 2026-06-14T11:29:46+00:00

Please have a look at the following code #include <iostream> #include <stdlib.h> #include <ctime>

  • 0

Please have a look at the following code

#include <iostream>
#include <stdlib.h>
#include <ctime>

using namespace std;

int main()
{
    enum Movement{STAND=1,WALK,RUN,CRAWL};

    srand(time(0));
    Movement state = (Movement)(1+rand()%4);

    for(int i=0;i<10;i++)
    {

    cout << state << endl;

    switch(state)
    {
        /*Here the logic is,
         * 
         * 1. From stand, he can walk or crawl
           2. From Walk, he can stand or run
           3. From Run, he can walk
           4. From Crawl, he can stand
         */

        case STAND: 
            cout << "You can walk or crawl" << endl;        
            while(state==WALK || state==CRAWL)
            {
                state = (Movement)(1+rand()%4);
            }
            break;


        case WALK: 
            cout << "You can stand or run" << endl;
            while(state==STAND || state==RUN)
            {
                state = (Movement)(1+rand()%4);
            }
            break;


        case RUN: 
            cout << "You can walk" << endl;
            while(state==WALK)
            {
                state = (Movement)(1+rand()%4);
            }
            break;

        default: 
            cout << "You can stand" << endl;
            while(state==STAND)
            {
                state = (Movement)(1+rand()%4);
            }

    }

    }
}

I am using random, and expecting random results based on those given conditions. But I am getting the same result as below.

2
You can stand or run
2
You can stand or run
2
You can stand or run
2
You can stand or run
2
You can stand or run
2
You can stand or run
2
You can stand or run
2
You can stand or run
2
You can stand or run
2
You can stand or run

why is this? I have tried do..while loops as well. No good at all. Nothing is checking the conditions I have given in case statements. please help.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-14T11:29:47+00:00Added an answer on June 14, 2026 at 11:29 am

    Flip your while-loops to do-while. The expressions are invalid as well for the checks (unless it was your intention they NOT match the text). The states, according to the messages are:

    Stand ==> (Walk || Crawl)
    Walk  ==> (Stand || Run)
    Run   ==> (Walk)
    Crawl ==> (Stand)
    

    So the sections need to be changed to

    1. Generate the new random number BEFORE checking it. and..
    2. Not leave until a valid production is reached.

    The latter part is important for the Run and Crawl states. Since they can only produce ONE valid result state, spinning a rand() call looking for that value makes no sense. Just set the new state and loop again.

    Regarding (2) above:

        case WALK: 
            cout << "You can stand or run" << endl;
            while(state==STAND || state==RUN)
            {
                state = (Movement)(1+rand()%4);
            }
            break;
    

    Becomes…

        case WALK: 
            cout << "You can stand or run" << endl;
            do {
                state = (Movement)(1+rand()%4);
            } while(state!=STAND && state!=RUN);
            break;
    

    Regarding the Run and Crawl states:

        case RUN: 
            cout << "You can walk" << endl;
            state = WALK;
            break;
    
        default: // CRAWL 
            cout << "You can stand" << endl;
            state = STAND;
            break;
    

    That leaves you one more to check yourself, which I leave to you.

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